Class 12 Case Study Questions on Vectors with Answers

Class 12 Case Study Questions on Vectors with Answers for Board Exam

Chapter: Class 12 Case Study Questions on Vectors

The chapter on Class 12 Case Study Questions on Vectors helps students understand vector algebra through practical and exam-focused case study problems. These questions follow NCERT patterns and, therefore, support effective revision. Moreover, each example is designed to improve conceptual clarity and strengthen problem-solving skills.

Core Vector Concepts Covered

This section includes dot product, cross product, vector magnitudes, direction ratios, and geometric interpretation. Additionally, students learn how to apply these concepts in real-world scenarios. The explanations are simple and highly useful during revision.

Advantages for Class 12 Board Preparation

These case studies enhance accuracy and exam readiness. Consequently, students gain confidence while solving higher-level vector problems. This structured material also helps them recall formulas quickly.

Class 12 Case Study Questions on Vectors with Answers

In a mechanics lab, a team is analyzing the motion of a block being pushed along an inclined plane. The **force applied** and the **displacement** are represented by vectors. To calculate the **work done** ($W = \vec{F} \cdot \vec{d}$), the students use the concept of **dot product** (or scalar product). They also explore how the dot product helps find the **angle between two vectors** and the **projection of one vector onto another**. The dot product is useful not only in physics but also in computer graphics, engineering, and navigation systems. By applying formulas, the students calculate work done, identify **orthogonal vectors**, and understand the geometric interpretations of the scalar product.

Theory and Formulae Related to Dot Product:

  • **Component Form**: $\vec{a} \cdot \vec{b} = a_1b_1 + a_2b_2 + a_3b_3$
  • **Geometric Form**: $\vec{a} \cdot \vec{b} = |\vec{a}||\vec{b}|\cos\theta$ [Image of geometric representation of dot product showing vectors a and b and angle theta]
  • **Angle between vectors**: $\cos\theta = \frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|}$
  • **Perpendicularity (Orthogonal Vectors)**: If $\vec{a} \cdot \vec{b} = 0$, then $\vec{a} \perp \vec{b}$.
  • **Projection of $\vec{a}$ on $\vec{b}$**: $\text{Proj}_{\vec{b}}\vec{a} = \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|}$

1. If $\vec{a} = 3\hat{i} – 2\hat{j} + \hat{k}$ and $\vec{b} = \hat{i} + 2\hat{j} + 3\hat{k}$, find $\vec{a} \cdot \vec{b}$.

Solution: $\vec{a} \cdot \vec{b} = 3(1) + (-2)(2) + 1(3) = 3 – 4 + 3 = 2$.
Correct answer is option **(c)**.

2. Two vectors $\vec{a}$ and $\vec{b}$ are perpendicular. Which condition is true?

Solution: If vectors are perpendicular, the angle between them is $\theta = 90^\circ$. Since $\vec{a} \cdot \vec{b} = |\vec{a}||\vec{b}|\cos\theta$, and $\cos(90^\circ) = 0$, then $\vec{a} \cdot \vec{b} = 0$.
Correct answer is option **(c)**.

3. If $|\vec{a}| = 5$, $|\vec{b}| = 6$, and angle between them is $60^\circ$, find $\vec{a} \cdot \vec{b}$.

Solution: Using $\vec{a} \cdot \vec{b} = |\vec{a}||\vec{b}|\cos\theta$: $\vec{a} \cdot \vec{b} = 5 \cdot 6 \cdot \cos 60^\circ = 30 \cdot \frac{1}{2} = 15$.
Correct answer is option **(b)**.

4. If $\vec{a} = 2\hat{i} + 2\hat{j}$ and $\vec{b} = \hat{i} – \hat{j}$, what is the angle between them?

Solution: First, calculate the dot product: $\vec{a} \cdot \vec{b} = 2(1) + 2(-1) = 2 – 2 = 0$. Since $\vec{a} \cdot \vec{b} = 0$, the angle $\theta$ must satisfy $\cos\theta = 0$, so $\theta = 90^\circ$.
Correct answer is option **(c)**.

5. The projection of $\vec{a} = 3\hat{i} + 4\hat{j}$ on $\vec{b} = 5\hat{i}$ is:

Solution:
1. Calculate $\vec{a} \cdot \vec{b}$: $\vec{a} \cdot \vec{b} = (3)(5) + (4)(0) = 15$.
2. Calculate magnitude of $\vec{b}$: $|\vec{b}| = \sqrt{5^2 + 0^2} = 5$.
3. Projection: $\text{Proj}_{\vec{b}}\vec{a} = \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|} = \frac{15}{5} = 3$.
Correct answer is option **(a)**.

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