math case study questions for class 8 on algebraic expressions

Math Case Study Questions for Class 8 on Algebraic Expressions

Math Case Study Questions for Class 8 on Algebraic Expressions

Explore engaging Math Case Study Questions for Class 8 on Algebraic Expressions to enhance your algebra learning. These practice sets blend theory with application-based math case study questions that improve critical thinking. Students can easily connect algebraic concepts to real-life examples, making problem-solving enjoyable and effective.

Understanding Algebra Through Case Studies

Each worksheet includes Case Study math questions for class 9 to help students transition smoothly between grades. Moreover, the exercises emphasize real-world problem solving, variable identification, and equation formation. With step-by-step solutions and guided hints, learners gain confidence and improve their analytical skills consistently.

Advanced Learning Practice

Our study material also integrates math case study questions class 9 to reinforce algebraic understanding. Additionally, transition words and logical flow ensure smooth learning progression from simple expressions to complex algebraic problems.

Wooden Tables Manufacturing Case Study Quiz

Case Study 3: Manufacturing of Wooden Tables using Algebraic Expressions

A furniture factory manufactures wooden tables. The cost of producing one table depends on the cost of wood and labor. The cost of wood for each table is represented by 5x + 20 rupees, where x is the cost of wood per square foot. The labor cost for producing n tables is represented by 2n(x + 10). The manager wants to find the total cost C for producing n tables, represented by:

C = n(5x + 20) + 2n(x + 10)

The production head simplifies, substitutes, and evaluates this expression for different values of x and n to estimate expenses and plan the budget. This case helps understand how algebraic expressions are used in real-world manufacturing and cost estimation.

MCQ Questions

1. Simplify the expression C = n(5x + 20) + 2n(x + 10).
Answer: (d)
Solution: C = n(5x + 20) + 2n(x + 10) = n(5x + 20 + 2x + 20) = n(7x + 40). Hence, the correct simplified form is C = 7nx + 40n, which is equivalent to n(7x + 40).
2. If x = 10 and n = 5, find the total cost.
Answer: (c)
Solution: C = 7(5)(10) + 40(5) = 350 + 200 = 550. Correct answer is 550, so correct option should be (c).
3. Identify the coefficient of x in the simplified expression C = 7nx + 40n.
Answer: (a)
Solution: The coefficient of x is 7n.
4. If the cost of wood increases by 5 rupees per square foot, find the new total cost expression.
Answer: (d)
Solution: Replacing x by x + 5: C = n(5(x + 5) + 20) + 2n((x + 5) + 10) = n(5x + 25 + 20) + 2n(x + 15) = n(5x + 45) + 2n(x + 15) = n(7x + 75). Simplified expression: C = 7nx + 75n. Hence, correct structure aligns with (d).
5. If n = 8, find the difference in total cost when x = 10 and x = 15.
Answer: (a)
Solution: For x = 10, C₁ = 7(8)(10) + 40(8) = 560 + 320 = 880. For x = 15, C₂ = 7(8)(15) + 40(8) = 840 + 320 = 1160. Difference = 1160 – 880 = 280.
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