Find the simplified form of cos⁻¹((3/5)cos x + (4/5)sin x) | NCERT EXEMPLAR Class 12 Maths Ex 2.3 Q13

NCERT Class 12 Mathematics Solutions – Exercise 2.3 Question 13

NCERT Class 12 Maths | Chapter 2 Inverse Trigonometric Functions

Question

Find the simplified form of \[ \cos^{-1}\left(\frac{3}{5}\cos x + \frac{4}{5}\sin x\right), \quad x \in \left[-\frac{3\pi}{4}, \frac{\pi}{4}\right] \]

[NCERT EXEMPLAR Ex 2.3, Question 13, Page 36]

Solution

We have,

\[ \cos^{-1}\left(\frac{3}{5}\cos x + \frac{4}{5}\sin x\right) \]

Let \[ \cos y = \frac{3}{5} \quad \Rightarrow \quad \sin y = \frac{4}{5} \]

Therefore, \[ y = \cos^{-1}\frac{3}{5} = \sin^{-1}\frac{4}{5} = \tan^{-1}\left(\frac{4}{3}\right) \]

Now, \[ \cos^{-1}(\cos y \cos x + \sin y \sin x) \]

\[ = \cos^{-1}(\cos(y – x)) \]

\[ = y – x \]

\[ \boxed{\tan^{-1}\left(\frac{4}{3}\right) – x} \]