Math Case Study for Class 8 Simple Interest

Math Case Study for Class 8 Simple Interest Case Study Online Test

Math Case Study for Class 8 Simple Interest Case Study

The Math Case Study for Class 8 Simple Interest Case Study introduces students to real-life money situations. It helps them understand how interest is calculated and applied. Moreover, it guides them in using SI formulas correctly while improving confidence.

Understanding Simple Interest Concepts

This section explains principal, rate, and time in simple steps. Students learn how these values interact. Additionally, short examples are added to make concepts easier. Every explanation supports revision and boosts clarity.

Applying Concepts Through Practice

The case study includes relatable problems. These tasks train students to think logically and calculate accurately. Furthermore, practice questions encourage step-by-step reasoning. With regular use, learners strengthen exam preparation.

Case Study 1: Simple and Compound Interest

Riya plans to start a small savings routine to support her long-term education goals. She visits a local bank that offers two types of investment schemes. The first is a **simple interest** saving account offering a fixed rate of interest per year. The second is a **compound interest** plan that compounds annually. To understand the difference, Riya deposits different amounts in both schemes for various durations and compares the final returns. She notices that even small changes in time period or rate significantly affect maturity amounts. Her goal is to choose the scheme that gives her the highest return while fitting her monthly saving capacity. She prepares a financial comparison table for principal amounts such as 4000, 5000, and 6000 rupees at rates from 5% to 12%. Based on these observations, she realizes the importance of calculating interest accurately for long-term planning. The following questions are based on Riya’s study of these investment schemes.

1. Riya invests Rs. 4000 at 10% per annum for 3 years in a simple interest account. What is the interest earned?

Solution:
Using the Simple Interest formula: $SI = \frac{P \times R \times T}{100}$
$SI = \frac{4000 \times 10 \times 3}{100} = 1200$
Hence, the correct answer is option **(b)**.

2. If Riya invests Rs. 5000 at 8% compound interest for 2 years (compounded annually), what will be the amount?

Solution:
Using the Compound Amount formula: $A = P(1+\frac{R}{100})^T$
$A = 5000(1+\frac{8}{100})^2 = 5000(1.08)^2$
$A = 5000 \times 1.1664 = 5832$
Correct answer is option **(a)**.

3. The simple interest on a sum for 5 years at 6% per annum is Rs. 1800. What is the principal?

Solution:
Using $SI = \frac{P \times R \times T}{100}$: $1800 = \frac{P \times 6 \times 5}{100}$
$P = \frac{1800 \times 100}{30} = 6000$
Correct answer is option **(b)**.

4. For a fixed principal, which factor increases the difference between compound interest (CI) and simple interest (SI) the most?

Solution:
The difference between CI and SI grows exponentially as the time period increases, because **compound interest** calculates interest on the interest earned in previous periods (compounding effect). Thus, **increase in time** increases the difference the most.
Correct answer is option **(b)**.

5. Riya deposits Rs. 6000 at 12% simple interest. How much total amount will she receive after 4 years?

Solution:
First, calculate the Simple Interest (SI): $SI = \frac{6000 \times 12 \times 4}{100} = 2880$
Total Amount = Principal + SI
Amount $= 6000 + 2880 = 8880$
Correct answer is option **(d)**.

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