Class 8 Percentage Profit Loss Discount Case Study

Class 8 Percentage Profit Loss Discount Case Study PDF

Class 8 Percentage Profit Loss Discount Case Study PDF

The Class 8 Percentage Profit Loss Discount Case Study PDF offers students practical maths problems based on daily life situations. These case studies explain how percentage, profit, loss, and discount work in real scenarios. Moreover, the worksheet helps students understand concepts clearly and improves overall accuracy.

Key Concepts Covered in the Case Study PDF

This PDF includes problems on cost price, selling price, profit percentage, loss percentage, and discount calculations. Additionally, the worksheet provides step-by-step solutions that guide students through each method. These concepts follow CBSE guidelines and support effective exam preparation.

Benefits of Practicing These Case Study Questions

The Class 8 Percentage Profit Loss Discount Case Study PDF strengthens logical thinking and boosts problem-solving skills. Furthermore, students gain confidence as they practice real application-based questions. The solved examples make revision simple and effective.

Mat Case Study Class 8: Class 8 Percentage Profit Loss Discount Case Study

A retail electronics market tested a price-strategy experiment during a month-long clearance and festival period. The store manager combined markups, successive discounts, flat discounts, bill-level coupons, and bundle offers to study both customer uptake and margin behaviour. For high-value items, the manager applied visible discounts to stimulate traffic while ensuring the shop did not incur large losses; for low-value fast-moving items, the manager used bill-level coupons to increase average basket size. The study recorded precise transaction data so that each sale could be traced from marked price to final payable amount and compared to cost price to compute exact profit or loss percentages. In many transactions, the manager needed to reverse-calculate cost from the final selling price when items had layered discounts. The dataset also included examples where rounding to two decimal places mattered for accounting, and cases where equivalent single-discount percentages were computed for reporting. Using this practical dataset, answer the MCQs below; all monetary values are in rupees.

1. A premium speaker has marked price Rs. 20000. During the festival, the store offers successive discounts of 10% and then 15%. What is the selling price?

Solution:
Marked price = 20000. After first discount of 10%, price becomes 20000 × 0.90 = 18000.
After second discount of 15%, price becomes 18000 × 0.85 = 15300.
Hence selling price is Rs. 15300. Option (a) is correct.

2. A blender is sold for Rs. 4680 after a single flat discount of 20% on the marked price. What was the marked price?

Solution:
Let marked price be M. After 20% discount, the selling price is M × 0.80 = 4680.
Thus M = 4680 / 0.80 = 5850.
Therefore, the marked price was Rs. 5850. Option (a) is correct.

3. A wristwatch has cost price Rs. 1500. The shop marks it at 25% above cost and then gives a single flat discount so that the seller still makes an 8% profit on cost. What is the discount percent on the marked price?

Solution:
Cost price = 1500. Marked price = 1500 × 1.25 = 1875.
Seller wants an 8% profit on cost, so selling price = 1500 × 1.08 = 1620.
Discount on marked price = (1875 – 1620) / 1875 × 100 = 13.60%.
Hence option (a) is correct.

4. A school purchases two sets of identical study-lamps priced Rs. 800 and Rs. 1200 (marked prices). The shop applies 10% discount on the total bill and then an additional 5% coupon on the discounted total. What is the total amount saved by the school and the effective percentage saved on the total marked price?

Solution:
Total marked price = 800 + 1200 = 2000. After 10% discount, the bill becomes 2000 × 0.90 = 1800.
After additional 5% coupon, the final payable amount is 1800 × 0.95 = 1710.
Total saved = 2000 – 1710 = 290. Effective percentage saved = (290 / 2000) × 100 = 14.50%.
Thus the school saved Rs. 290, which is 14.50% of the total. Option (a) is correct.

5. A gadget is marked 40% above cost and then sold after successive discounts of 10% and 5% to give a final selling price Rs. 5544. What was the cost price?

Solution:
Let cost price be C. Marked price = 1.40 × C. Successive discounts multiply the marked price by 0.90 × 0.95 = 0.855.
Thus final selling price = 1.40 × C × 0.855 = 1.197 × C.
We are given selling price = 5544, so C = 5544 / 1.197 ≈ 4631.58.
Therefore option (a) is correct.

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