Exponents and Standard Form Case Study Questions Class 8

Class 8 Maths Case Study on Exponents

Class 8 Maths Case Study on Exponents

Learn Class 8 Maths Case Study on Exponents and understand how powers and standard forms make numbers easier to handle. This topic builds a strong base for algebra and scientific calculations. Moreover, it helps students solve real-life mathematical problems confidently.

Key Concepts in Exponents and Powers

In this case study, you will explore laws of exponents, powers with negative exponents, and how to express numbers in standard form. Additionally, the examples and questions are based on the latest CBSE Class 8 Maths syllabus, making the learning experience relevant and practical.

Video Tutorial and Practice Questions

Watch our video tutorial on Exponents and Powers for Class 8 to grasp each concept easily. Furthermore, download PDF worksheets and practice questions to test your understanding. As a result, you will improve your speed, accuracy, and confidence in solving case study questions on Exponents and Powers.

Compound Growth and Currency Case Study

Case Study 4: Class 8 Maths Case Study on Exponents

A group of students from Class 8 studied how exponents are used in finance to represent large numbers and compound growth. Their school organized a mock investment activity. Each student was given a virtual investment of Rs. \(5 \times 10^3\). The virtual interest rate was 10% per year, compounded annually. The challenge was to calculate the value of their investment after 3 years using the formula \(A = P(1 + r)^t\), where \(P\) is the principal, \(r\) is the rate (in decimal), and \(t\) is the time in years.

In addition, they compared their final amounts with a class fund of Rs. \(1 \times 10^6\) and learned how large monetary figures are represented in standard form in banking and economics. Through this activity, the students understood the real-life application of exponents in financial growth and large value representation.

MCQ Questions:

1. What is the value of each student’s investment after 3 years at 10% interest compounded annually?
Solution:
\(A = 5 \times 10^3 (1 + 0.1)^3 = 5 \times 10^3 (1.331) = 6.655 \times 10^3 \approx 6.55 \times 10^3.\)
2. Represent Rs. 6,550 in standard form.
Solution:
To convert 6,550, move the decimal three places left: \(6.55 \times 10^3.\)
3. The total investment of 100 students at the end of 3 years would be approximately:
Solution:
Total \(= 100 \times 6.55 \times 10^3 = 1 \times 10^2 \times 6.55 \times 10^3 = 6.55 \times 10^{5}.\)
4. If the class fund is Rs. \(1 \times 10^6\), how many times greater is it than one student’s final investment?
Solution:
\(\dfrac{1 \times 10^6}{6.55 \times 10^3} \approx \dfrac{1}{6.55} \times 10^{6-3} \approx 0.15 \times 10^3 \approx 10^2.\)
5. If the same investment continues for 5 years at 10% interest, find the approximate amount.
Solution:
\(A = 5 \times 10^3 (1.1)^5 = 5 \times 10^3 \times 1.6105 = 8.05 \times 10^3.\)
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