class 8 math case study on algebraic expressions

Class 8 Math Case Study on Algebraic Expressions | CBSE Practice

Class 8 Math Case Study on Algebraic Expressions

The Class 8 Math Case Study on Algebraic Expressions helps students explore algebra through real-world applications and math case study questions. These worksheets make complex algebraic concepts simple, interactive, and fun to learn. Moreover, students gain confidence by solving practical problems using equations and variables.

Key Learning Objectives

Each study set includes Case Study math questions for class 9 to enhance reasoning and problem-solving abilities. Additionally, students practice analytical skills by applying algebraic rules in daily scenarios. The transition from theoretical understanding to practical application ensures a deeper grasp of key mathematical concepts.

Practice and Application

Through our worksheets, learners engage with math case study questions class 9 and advanced algebra exercises. Furthermore, the guided steps and transition words ensure clarity, making learning structured and enjoyable for every Class 8 student.

School Garden Case Study Quiz

Case Study 2: Designing a School Garden using Algebraic Expressions

The Eco Club of a school decided to design a rectangular garden. The length of the garden is represented by the expression 3x + 4 meters, and its breadth is represented by x + 2 meters. The club also plans to build a small walkway around the garden, which costs 50 rupees per meter of the garden’s perimeter. The total area and total cost of fencing and walkway construction are to be calculated using algebraic expressions. The students realized that using algebra helped them to generalize the design and compute costs easily when the dimensions changed.

They used the formula for perimeter P = 2(l + b) and area A = l × b. They further substituted values for x to estimate the expenses for various garden sizes.

MCQ Questions

1. Find the expression for the perimeter of the garden.
Answer: (d)
Solution: P = 2(l + b) = 2[(3x + 4) + (x + 2)] = 2(4x + 6) = 8x + 12. Hence, all forms are equivalent.
2. Find the area of the garden in terms of x.
Answer: (a)
Solution: A = (3x + 4)(x + 2) = 3x² + 6x + 4x + 8 = 3x² + 10x + 8.
3. If the walkway costs 50 rupees per meter, find the expression for total cost C in terms of x.
Answer: (c)
Solution: C = 50 × P = 50(8x + 12) = 400x + 600. Both are equivalent.
4. If x = 3, find the area of the garden.
Answer: (c)
Solution: Substituting x = 3 in A = 3x² + 10x + 8: A = 3(9) + 30 + 8 = 27 + 38 + 8 = 77 m². Hence, option (c).
5. If x = 2, calculate the total cost of walkway construction.
Answer: (a)
Solution: C = 400x + 600 = 400(2) + 600 = 800 + 600 = 1400. Correction: none of the options match; correct answer is 1400 rupees. Option (a) should be replaced with 1400.
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