Class 8 Discount Case Study Questions with Solutions

Class 8 Discount Case Study Questions with Solutions

The Class 8 Discount Case Study Questions with Solutions provide students with practical price-based problems. These questions teach how to calculate discount, marked price, and selling price correctly. Moreover, they help students understand real-life shopping situations using simple maths examples. This improves accuracy and confidence during exams.

Topics Covered in Class 8 Discount Case Studies

The worksheet includes important concepts like discount percentage, cost comparison, and profit after discount. Additionally, it explains step-by-step solutions, which allow students to learn methods clearly. These structured questions follow the latest CBSE guidelines, making them highly useful.

Why Students Should Practice These Questions

The Class 8 Discount Case Study Questions with Solutions strengthen logical thinking through application-based problems. Furthermore, regular practice helps students score better marks in mathematics. The clear solutions ensure easy revision and faster learning.

Case Study Questions Class 8 Math – 3 : lass 8 Discount Case Study Questions with Solutions

A mid-sized grocery chain ran a month-long promotional study to understand the impact of different discount strategies on customer behaviour and margins. During the study, the marketing team used combinations of successive discounts, single flat discounts, and bill-level coupons. They also tested marking certain seasonal items above cost so that discounts would still allow a reasonable profit. The managers recorded data for individual items as well as for bundle purchases. In addition, they tracked cases where the selling price produced an exact, fractional, or recurring rupee value to study transaction rounding effects. The objective was to compute effective discounts, final selling prices, profit or loss percentages, and total customer savings for single items and bundles. The study required careful reverse calculations to find cost prices from given marked prices and observed profit percentages. Use the data from this grocery study below to answer the questions. All monetary values are in rupees.

1. A home appliance has a marked price of Rs. 12500. The store offers successive discounts of 20 percent followed by 10 percent. What is the selling price?

Solution:
Marked price = Rs. 12500. First discount 20 percent reduces price to 12500 × 0.80 = 10000.
Second discount 10 percent reduces it to 10000 × 0.90 = 9000.
Thus selling price = Rs. 9000. Option (b) is correct.

2. A pair of shoes is sold at a marked price that is 25 percent above its cost price. If the marked price is Rs. 5250 and the shop gives a flat discount of 15 percent on the marked price, the shoe still yields a profit. If the cost price is Rs. 4200, what is the profit percent obtained?

Solution:
Given cost price = Rs. 4200. Marked price is Rs. 5250 which matches 25 percent above cost since 4200 × 1.25 = 5250.
Selling price after 15 percent discount = 5250 × 0.85 = 4462.50.
Profit amount = 4462.50 – 4200 = 262.50.
Profit percent = (262.50 / 4200) × 100 = 6.25%.
Thus option (b) is correct.

3. A boutique applies successive discounts of 12 percent and 18 percent on a dress. What single flat discount percent is equivalent to these successive discounts (rounded to two decimal places)?

Solution:
Take an initial price of 100 units. After 12 percent discount price becomes 100 × 0.88 = 88.
After further 18 percent discount price becomes 88 × 0.82 = 72.16.
Effective price fraction = 0.7216. Effective discount = 1 – 0.7216 = 0.2784 = 27.84%.
Rounded to two decimal places the equivalent single discount is 27.84 percent. Option (b) is correct.

4. A school buys 10 identical study tables, each with marked price Rs. 1500. The supplier offers 10 percent discount on the total bill and an additional 5 percent corporate coupon on the discounted bill. What is the total amount saved by the school and what is the effective percentage saved on the total marked price?

Solution:
Total marked price = 10 × 1500 = 15000.
After 10 percent discount: 15000 × 0.90 = 13500.
After additional 5 percent coupon: 13500 × 0.95 = 12825.
Total saved = 15000 – 12825 = 2175.
Effective percentage saved = (2175 / 15000) × 100 = 14.50%.
Thus option (a) is correct.

5. A kitchen mixer has marked price Rs. 3500. During a promotion the store gives 20 percent discount on the marked price and yet records a profit of 12 percent on the sale. What is the cost price of the mixer?

Solution:
Selling price after 20 percent discount = 3500 × 0.80 = 2800.
Let cost price be C. Given profit is 12 percent so 2800 = C × 1.12.
Hence C = 2800 ÷ 1.12 = 2500.
Therefore option (b) Rs. 2500 is correct.

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