CBSE Class 8 Exponents Case Study with Solutions

CBSE Class 8 Exponents Case Study with Solutions

The CBSE Class 8 Exponents Case Study with Solutions explains how to simplify large numbers using powers and laws of exponents. Moreover, students can learn how to apply these mathematical rules to real-life examples for better conceptual understanding. Each case study is based on the CBSE Class 8 Maths syllabus.

Important Topics Covered

This section includes laws of exponents, powers with negative integers, and numbers in standard form. Additionally, these solved case study questions are designed to strengthen analytical skills and mathematical accuracy.

Video Tutorials and Practice Resources

Watch our video tutorials on Exponents and Powers for Class 8 to gain a clearer understanding. Furthermore, download free CBSE Class 8 Exponents PDFs with detailed solutions and practice questions to prepare effectively for your exams.

Space Research and Measurement Case Study

Case Study 2: CBSE Class 8 Exponents Case Study with Solutions

During a science exhibition, students created a model of a rocket launch simulation. To understand real-life space measurements, they studied how scientists use exponents and powers in expressing large and small quantities. The average distance between Earth and Moon is approximately \(3.84 \times 10^5\) km, while the speed of light is \(3 \times 10^8\) m/s. For their simulation, they designed a miniature spacecraft that could travel at \(2 \times 10^3\) m/s. The team wanted to calculate how long it would theoretically take their spacecraft to reach the Moon if it could travel directly. They also learned to express very small values like mass of particles and large distances using scientific notation to make comparisons easier. This project helped them appreciate how exponents simplify real-world scientific data representation.

MCQ Questions:

1. Convert the speed of the spacecraft \(2 \times 10^3\) m/s into km/s.
Solution:
\(1 \text{ km} = 10^3 \text{ m}\). Therefore, \(2 \times 10^3 \text{ m/s} = 2 \times 10^3 \times 10^{-3} = 2 \times 10^{0} = 2 \text{ km/s.}\) Hence, in km/s, exponent form is \(2 \times 10^{0}\).
2. If the Moon is \(3.84 \times 10^5\) km away, how many seconds will the spacecraft take to reach it at a speed of \(2 \text{ km/s}\)?
Solution:
Time \(= \dfrac{\text{distance}}{\text{speed}} = \dfrac{3.84 \times 10^5}{2} = 1.92 \times 10^5\) s.
3. Express \(0.00012\) in standard form.
Solution:
\(0.00012 = 1.2 \times 10^{-4}\) since the decimal is moved 4 places to the right.
4. The mass of a dust particle is \(3 \times 10^{-7}\) kg and there are \(2 \times 10^3\) such particles. What is the total mass?
Solution:
Total mass \(= 3 \times 10^{-7} \times 2 \times 10^3 = 6 \times 10^{-7+3} = 6 \times 10^{-4}\) kg.
5. Which of the following represents a larger number?
Solution:
Comparing powers of 10, the greatest exponent corresponds to the largest number. Hence, \(10^7\) is greater than \(10^6, 10^5, 10^4.\)
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