algebraic expressions case study for class 8 pdf

Algebraic Expressions Case Study for Class 8 PDF Download

Algebraic Expressions Case Study for Class 8

Learn algebra effectively with our Algebraic Expressions Case Study for Class 8. This study material simplifies key algebraic concepts through real-life examples and math case study questions. Students gain confidence in using variables, constants, and coefficients in practical contexts, improving overall problem-solving skills.

Concept Building Through Case Studies

Each case study includes step-by-step guidance and Case Study math questions for class 9 to bridge learning gaps. These exercises are designed to build strong analytical foundations while making algebra engaging and easy to understand. Moreover, they introduce logical reasoning through everyday math situations, ensuring smooth conceptual clarity.

Real-world Math Practice

Our worksheets include math case study questions class 9 to strengthen analytical skills. Additionally, transition-based examples guide learners from simple equations to complex expressions, enhancing their readiness for higher-level mathematics.

Stationery Business Profit Calculation Case Study Quiz

Case Study 4: Profit Calculation in a Stationery Business using Algebraic Expressions

A stationery shop sells notebooks and pens. The cost of one notebook is represented by 3x + 10 rupees, and the cost of one pen is represented by x + 5 rupees, where x represents the variable component due to market changes. The shopkeeper sells m notebooks and n pens in a day. The total revenue R is represented by:

R = m(3x + 10) + n(x + 5)

The total cost C for buying these goods from the wholesaler is given by:

C = m(2x + 8) + n(x + 3)

The shopkeeper wants to calculate the profit P = R – C, simplify the expression, and analyze how changes in x, m, and n affect his business. This case study shows how algebraic expressions can help in financial planning and decision-making.

MCQ Questions

1. Find the simplified expression for profit P = R – C.
Answer: (d)
Solution: P = [m(3x + 10) + n(x + 5)] – [m(2x + 8) + n(x + 3)] = (3mx + 10m + nx + 5n) – (2mx + 8m + nx + 3n) = mx + 2m + 2n. Hence, (b) and (c) are equivalent.
2. If x = 10, m = 20, and n = 30, find the total profit.
Answer: (c)
Solution: P = mx + 2m + 2n = (20)(10) + 2(20) + 2(30) = 200 + 40 + 60 = 300.
3. Identify the constant term in the simplified expression for profit.
Answer: (a)
Solution: The term without a variable is 2m + 2n, which is the constant part.
4. If the shopkeeper increases the price of notebooks by 5 rupees, what will be the new profit expression?
Answer: (d)
Solution: Increasing notebook price by 5 means revenue increases by 5m. So, Pnew = (mx + 2m + 2n) + 5m = mx + 7m + 2n.
5. If m = 10 and n = 15, find the profit when x = 12.
Answer: (c)
Solution: P = mx + 2m + 2n = 10(12) + 20 + 30 = 120 + 50 = 170.
Educational Resources Footer
GitHub