CBSE Class 8 Exponents Case Study with Solutions

Exponents and Standard Form Case Study Questions Class 8

Exponents and Standard Form Case Study Questions Class 8

The Exponents and Standard Form Case Study Questions Class 8 focus on understanding powers, laws of exponents, and the use of standard form in mathematics. Moreover, these case studies improve problem-solving and logical reasoning skills among students, aligning with the CBSE Class 8 Maths syllabus.

Key Concepts of Exponents and Standard Form

In this chapter, students will learn how to express large numbers in standard form and apply laws of exponents like product, quotient, and zero exponent rules. Additionally, each solved example enhances conceptual clarity and exam readiness.

Video Tutorial and Practice Resources

Watch our video tutorial on Exponents and Standard Form for Class 8 to master each concept visually. Furthermore, download free PDF worksheets and case study questions with solutions to practice effectively and score better in exams.

Population Growth and Use of Exponents Case Study

Case Study 3: Exponents and Standard Form Case Study Questions Class 8

A group of geography students were researching how population changes over time can be expressed using powers and exponents. They studied a city that had a population of \(2 \times 10^5\) people in the year 2000. Every 10 years, the population increased by a factor of \(2 \times 10^0\) (i.e., it doubled every decade). The students wanted to predict the population for the years 2010, 2020, and 2030. They also compared it with another town whose growth rate was slower — it increased only by a factor of \(5 \times 10^{-1}\) per decade. By applying the laws of exponents and converting their results into standard form, they could easily analyze long-term growth trends and make population projections.

MCQ Questions:

1. What will be the population of the city in 2010?
Solution:
Each decade population doubles, so \(2 \times 10^5 \times 2 = 4 \times 10^5\).
2. What will be the population of the city in 2020?
Solution:
In 20 years, it doubles twice. Population \(= 2 \times 10^5 \times 2^2 = 2 \times 4 \times 10^5 = 8 \times 10^5\).
3. The other town grows by a factor of \(5 \times 10^{-1}\) per decade. If its population in 2000 was \(2 \times 10^5\), what is its population in 2010?
Solution:
\(2 \times 10^5 \times 5 \times 10^{-1} = (2 \times 5) \times 10^{5-1} = 10 \times 10^4 = 1 \times 10^5.\)
4. By 2030, what will be the population of the first city if it continues to double every 10 years?
Solution:
\(2 \times 10^5 \times 2^3 = 2 \times 8 \times 10^5 = 1.6 \times 10^6.\)
5. If the population of the smaller town decreases to half every decade, express its 2030 population as a power of 10 starting from \(2 \times 10^5\).
Solution:
It halves thrice (2000–2010–2020–2030): \(2 \times 10^5 \times (10^{-1})^3 = 2 \times 10^{5-3} = 2 \times 10^2 = 2 \times 10^4.\)
Educational Resources Footer
GitHub