Grade 7 Percentage Word Problems Test

Grade 7 Percentage Word Problems Test

Overview of the Grade 7 Percentage Word Problems Test

The Grade 7 Percentage Word Problems Test helps students understand how percentages apply to real situations. These questions improve logical thinking and strengthen basic arithmetic skills. Moreover, the test guides learners in solving problems based on discounts, profit and loss, tax, and simple interest. Students gain confidence through repeated practice.

Learning Through Real-Life Percentage Applications

Percentage word problems teach students how math works in everyday life. They learn to convert fractions and decimals, analyze data, and apply formulas correctly. Additionally, these problems improve decision-making skills. Many activities encourage step-by-step reasoning, making the learning experience effective and enjoyable. Regular practice leads to steady improvement.

Why Practice Matters

Frequent practice helps students master concepts faster. It also builds accuracy and supports long-term understanding.

Mathematics Assessment | Focus: Percentage, Discount, Interest, Increase/Decrease

Instructions: This test contains 15 Multiple Choice Questions. Choose the single best answer.

Q1. A shirt originally costs \$40 and is on sale for 25\% off. What is the sale price?
Answer: (B) \$30
Explanation: Discount = $0.25 \times \$40 = \$10$. Sale price = $\$40 – \$10 = \$30$.
Q2. If the population of a town increased from 8,000 to 9,200, what is the percentage increase?
Answer: (D) 15\%
Explanation: Increase = $9,200 – 8,000 = 1,200$. Percentage increase = $\frac{1,200}{8,000} \times 100 = 0.15 \times 100 = 15\%$.
Q3. What is 35\% of 280?
Answer: (C) 98
Explanation: $0.35 \times 280 = 98$.
Q4. A car’s value depreciated by 20\% each year. If it was worth \$25,000 new, what is its value after one year?
Answer: (A) \$20,000
Explanation: Depreciation amount = $0.20 \times \$25,000 = \$5,000$. Value = $\$25,000 – \$5,000 = \$20,000$.
Q5. If 15\% of a number is 45, what is the number?
Answer: (B) 300
Explanation: Let the number be $x$. $0.15x = 45$. $x = 45 \div 0.15 = 300$.
Q6. A store offers a 15\% discount on all items. If a customer buys a laptop priced at \$800, how much will they pay?
Answer: (A) \$680
Explanation: They pay $100\% – 15\% = 85\%$ of the price. $0.85 \times \$800 = \$680$. (Discount is $0.15 \times \$800 = \$120$. Price paid is $\$800 – \$120 = \$680$).
Q7. The pie chart below shows the distribution of 600 students by grade level. How many students are in Grade 7 (45\%)?
Answer: (B) 270
Explanation: Grade 7 is $45\%$ of 600 students. $0.45 \times 600 = 270$ students.
Q8. Calculate the simple interest on \$5,000 at 8\% per annum for 3 years.
Answer: (C) \$1,200
Explanation: Simple Interest (SI) = $P \times R \times T = \$5,000 \times 0.08 \times 3 = \$1,200$.
Q9. A product’s price increased from \$60 to \$75. What is the percentage increase?
Answer: (B) 25\%
Explanation: Increase = $\$75 – \$60 = \$15$. Percentage increase = $\frac{15}{60} \times 100 = 0.25 \times 100 = 25\%$.
Q10. After a 20\% discount, a book costs \$24. What was its original price?
Answer: (B) \$30
Explanation: The sale price (\$24) is $100\% – 20\% = 80\%$ of the original price ($x$). $0.80x = 24$. $x = 24 \div 0.8 = \$30$.
Q11. In a class of 40 students, 55\% are girls. How many boys are in the class?
Answer: (B) 18
Explanation: If $55\%$ are girls, then $100\% – 55\% = 45\%$ are boys. Number of boys = $0.45 \times 40 = 18$ boys.
Q12. If the sales tax is 7\% and you buy an item for \$150, what is the total amount paid?
Answer: (C) \$160.50
Explanation: Tax = $0.07 \times \$150 = \$10.50$. Total paid = $\$150 + \$10.50 = \$160.50$.
Q13. A company’s profits decreased from \$80,000 to \$68,000. What is the percentage decrease?
Answer: (D) 15\%
Explanation: Decrease = $\$80,000 – \$68,000 = \$12,000$. Percentage decrease = $\frac{12,000}{80,000} \times 100 = 0.15 \times 100 = 15\%$.
Q14. What percentage of 250 is 75?
Answer: (C) 30\%
Explanation: $\frac{75}{250} \times 100 = 0.3 \times 100 = 30\%$.
Q15. A bank offers 5\% simple interest per year. How much money should be invested to earn \$300 interest in 4 years?
Answer: (C) \$1,500
Explanation: Use $SI = P \times R \times T$. We have $300 = P \times 0.05 \times 4$. $300 = 0.2P$. $P = 300 \div 0.2 = \$1,500$.

Results Summary

Total Questions: 15

Correct Answers: 0

Percentage Score: 0%

Review the questions above to see the correct options and detailed explanations.

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